127
3 3h
(K )
3 Z 3 Z
K ( h h ) K ( h h )
+1/2J i+lj i,j i-1/2,j i,j i-l,j
(70)
2
Az
13 3 h 1
_(_(rK _)) = (r K (h -h )
r 3r 3r 2 i,j+l/2 i,j+l/2 i,j+l i,j
r Ar
i.j
- r K ( h h ) ) (71)
iJ-1/2 i.j-1/2 i.j i,j" 1
K K
3 K i-1/2, j 1+1/2,j
(72)
Equation (68) was divided into two parts and arranged such that the
unknowns are on the left side of the equations and the knowns are on the
right side such that
1 At
( 2
2 Ar
ri,j-l/2
r
i.j
k+1/2
K
i-1/2,j k+1/2
) h
i.j-1
C
i.j
k+1/2
1 At ( r K
i,j+1/2 i,j+1/2
+ (
k+1/2
+ r K )
i.j-1/2 l.j-1/2
+ 1 )
k+1/2
h
i.j
2
2
Ar r C
i.j i.j